The Locus of the point $P$, such that sum of squares of its distances from $(1,2)$ and $(3,4)$ is $25$ units, is $x^2+y^2-4x-6y+k=0$. Then $k =$ ?
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Tried anything yourself? The question could be worded better as well. – Aug 27 '15 at 05:32
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^ @mistermarko, done. – Apurv Aug 27 '15 at 05:42
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2$(x-1)^2+(y-2)^2+(x-3)^2+(y-4)^2=25$. Expand, and compare with the given equation. – André Nicolas Aug 27 '15 at 05:53