There are three important things that you need to think about:
- Things can miss each other, i.e. be "disjoint". For example, what is the intersection of the points $(0,0)$ and $(1,1)$? What about the lines $y=x$ and $y=x+1$.
- If they do intersect, what if they overlap? In two dimensions: the line $y=x$ and the line $x-y=0$ intersect along a line. In three dimensions: the planes $x=0$ and $y=0$ meet along a line, but the planes $x=0$ and $2x=0$ meet in a plane.
- If the objects do intersect, then the number of dimensions you're working in is important. For example: are you in the plane, or in 3d, or 4d?
In three dimensions, intersecting planes usually meet along a line. In four dimensions they usually meet at a point.
This can all get quite complicated. In three dimensions, a plane is given by one linear equation, e.g. $x+2y+3z=1$. Solving that one equation imposes one condition and makes you drop down from all of 3d to a 2d plane. To intersect two planes you need to solve two equations at once. So you impose two conditions, say $x=0$ and $y=0$. That drops you down from 3d to 1d. You have imposed two conditions, or used two degrees of freedom, so you drop down by two dimensions.
In four dimensions, a plane is given by two equations. A plane is 2d and so solving two equations drops you down from 4d to a 2d plane. Intersecting two planes in 4d means you have to solve four equations at once. So you use up four degrees of freedom and drop down from 4d to 0d, i.e. a point.
That is what usually happens. Sometimes things are more complicated. Again in 4d. What is one plane has equations $x=0$ and $y=0$, and the other has equations $y=0$ and $z=0$? These aren't really four equations. The equation $y=0$ appears twice. There are only three "independent" equations. So you have only imposed three conditions, you have only used three degrees of freedom. You will only drop down from 4d to 1d. This time, the planes intersect to give a line.
Take a look at this Wikipedia article on "Systems of Linear Equations".