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If $f(z)=0$ for some $z\in D$ then since $0$ is a constant, $f'(z)=0$ on $D$. Also since $f$ is analytic, then by theorem $f(z)$ is constant.

Here is where I get stock!

If $f(z)\not=0$. I want to show that $\operatorname{Re}f$ and $\operatorname{Im}f$ are constant using the hint that $\bar f=|f|^2/f.$

hanna
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1 Answers1

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Hint: Note that $\overline f=\frac cf$ is analytic.