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the question is to turn this question {1/4} double root to standard form.

What i got is x = 1/4, x= 1/4 once you multiply them you get x^2 -1/2x -1/16 I think not sure if I'm correct

and thanks to who ever it is that edits my question...i don't know how to write it in a proper way and am learning but thanks

MATH ASKER
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    Not even addressing the fact that I have no idea what you're asking here, this page will explain how to format your math. It's not that hard. For instance, to make x^2 -1/2x -1/16 look nicer, just throw a $ in front of and after it to get $x^2 -1/2x -1/16$. Or even better, use $x^2 - \frac {1}{2}x - \frac {1}{16}$ to get $x^2 - \frac {1}{2}x - \frac {1}{16}$ or $x^2 - \dfrac {1}{2}x - \dfrac {1}{16}$ to get $x^2 - \dfrac {1}{2}x - \dfrac {1}{16}$. –  Sep 08 '15 at 22:07

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You are correct. For any two roots $a$ and $b$, the quadratic with those roots is $0 =(x-a)(x-b) =x^2-(a+b)x + ab $.

If $a = b = \frac14$, the quadratic is $x^2-(\frac14+\frac14)x+\frac14\cdot \frac14 =x^2-\frac12x+\frac1{16} $.

marty cohen
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