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$(1-(1-(1-n)^{-1})^{-1})^{-1}$

Please tell me how to solve the abv sum. The ans is $n$

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swati aayush
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    This question does not deserve the downvotes,instead the OP should be advised on how to write a good question on this site. – Nicco Oct 05 '15 at 07:35
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1 Answers1

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$(1-(1- (1-n)^{-1})^{-1})^{-1} =\left(1- \left(1 + \dfrac{1}{n-1}\right)^{-1}\right)^{-1}=\left(1-\left(\dfrac{n}{n-1}\right)^{-1}\right)^{-1}=\left(1-\dfrac{n-1}{n}\right)^{-1}= \left(\dfrac{1}{n}\right)^{-1}= n$

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