Let's say that $X$ and $Y$ are vector spaces and to be more accurate $Y$ is a dense subspace of $X$. Furthermore we have that $(f_n)_{n\in\mathbb{N}}$ is a sequence in $X^*$, $f\in X^*$ and that $f_n$ converges pointwise to $f$ on $Y$. Can we deduce using continuity and density arguments that $f_n$ converges pointwise to $f$ on $X$?
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Does $X^$ denote the set of all continuous* linear functionals on $X$? – sranthrop Oct 10 '15 at 09:04
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You can conclude the pointwise convergence on $X$ if the sequence is equicontinuous. – Daniel Fischer Oct 10 '15 at 09:42
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Daniel do u mean equicontinuous on $Y$? – Perpendicular Oct 10 '15 at 09:54
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Now we cannot. Let $X = c_0$ (the convergent sequences) and $Y = c_{00}$, the subspace of sequences with are zero finally. Define $f_n \in c_0^*$ by $$ f_n(x) = nx_n, $$ then, for any $y \in c_{00}$, we have that $f_n(y) = 0$ finally, hence $f_n|_{c_{00}} \to 0$ pointwise. But, for $x = (1/n) \in c_0$, we have $f_n(x) = 1$ for all $n$, that is $f_n \not\to 0$.
martini
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