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Define a function $\varphi : \mathbb{N} \rightarrow \mathbb{N}$ as follows.

$$\varphi(n) = \sum_{i=1}^n \left[\binom{n}{i} \prod_{j=1}^i(i-j+1)^{2^j}\right]$$

The motivation is that according to this article, we have: for all natural $n$, $\varphi(n)$ is the cardinality of the free band on $n$ generators.

Questions.

I'd like to learn more about $\varphi$.

Q0. Does it have a standard name?

Q1. Are there other, apparently unrelated counting problems to which $\varphi$ is the solution?

Q2. Does $\varphi$ satisfy any interesting identities?

Q3. If so, is there a good resource for learning these identities?

Remark. This function helps explain where the number $14$ comes from in the Kuratowski closure-complement theorem. Basically, this happens because $$2(\varphi(2)+1) = 2(6+1) = 14.$$

To see the relevance of $\varphi(2),$ note that if $X$ is a topological space, then letting $k_X$ and $i_X$ denote the closure and interior operators on $X$ respectively, then the semigroup $S_X$ generated by $\{k_X,i_X\}$ is a band; furthermore, we can choose $X$ appropriately (e.g. $X = \mathbb{R}$) such that $S_X$ is the free band on these two elements.

goblin GONE
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    The sequence is registered in OEIS. It has the number A030449. It seems like that there is no evident research about the sequence. – Hanul Jeon Oct 11 '15 at 09:53
  • The original reference is [1] Green, J. A. Rees, D. On semi-groups in which $x^r=x$, Proc. Cambridge Philos. Soc. 48, (1952) 35-40. Another proof can be found in [2] Lallement, Gérard. Semigroups and combinatorial applications. Pure and Applied Mathematics. A Wiley-Interscience Publication. John Wiley & Sons, New York-Chichester-Brisbane, 1979. xi+376 pp. ISBN: 0-471-04379-6, pp 300-302 – J.-E. Pin Oct 11 '15 at 12:31
  • The value of $\varphi(n)$ is better understood if you analyse the $\mathcal{J}$-structure of the free band with $k$ generators. The $\mathcal{J}$-classes are indexed by subsets of ${1, \ldots, k}$. The $\mathcal{J}$-classes indexed by subsets of size $j$ all have the same size $c_j$, where $c_1 = 1$ and $c_j = j^2c_{j-1}^2$. – J.-E. Pin Oct 11 '15 at 12:38

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