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If A is a $m$ $x$ $n$ matrix such that: $Ax = 0$, for every $x \in \mathbb{R}^n$, then A = 0 is the zero matrix.

I have no idea how to begin proving this. The only hint is to consider a $j$ column in the Identity matrix $I_n$, but I don't see how that helps. Can anyone help me?

q.Then
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2 Answers2

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The $j$th column of the matrix $A$ is the image of the $j$th coordinate vector under $A$. Now what does the question tell us about these images?

Daron
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To see what goes on, take an arbitrary non-zero $2\times 2$ matrix. Assume for a second all its entries are non-zero. Can you think of a single $x\in \mathbb R^2$ with $Ax\ne 0$? Now, what happens if one or more of the entries (but not all!) are zero? what can you do? Now what happens if it's an arbitrary matrix?

Ittay Weiss
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  • I can see why A must be the zero matrix when you explained it like this, but how do I give a proof of showing concretely that A is the zero matrix? – q.Then Oct 15 '15 at 23:39
  • Let $A\ne 0$ be an arbitrary metric satisfying the stated property. We may assume the entry $a_{ij}\ne 0$. But then ... contradicting the given property of the matrix. – Ittay Weiss Oct 15 '15 at 23:41