I need to find the 6th term of $(4x-\frac{1}{2x})^{10}$
To my knowledge, the 6th term would be:
$\binom{10}{6}$$(4x)^6$$(-\frac{1}{2x})^{4}$ = 210*4096$x^6$$(\frac{1}{16x^4})$ = 53760$x^2$...but the answer is -8064. What went wrong?
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1Sixth term, count on fingers. First involves $\binom{10}{0}(4x)^{10}$, second $\binom{10}{1}(4x)^9$, and so on sixth term is $\binom{10}{5}(4x)^5()^?$. – André Nicolas Nov 03 '15 at 04:39
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D'oh! Sorry....thank you for catching that. – Alvin Nunez Nov 03 '15 at 04:40
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You are welcome. In principle $6$th term is unambiguous, but it doesn't quite work out that way. – André Nicolas Nov 03 '15 at 04:42