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A circular disk is divided into $5$ equal segments. On spinning the disk a pointer always points to one segment. The segments contain pictures of $2$ bananas, $2$ lemons and one kiwi fruit. The disk is spun $4$ times.

The probability of not getting a kiwi is $\frac45 \times \frac45 \times \frac45 \times \frac45 = 0.410$.

The probability of getting one kiwi is $(\frac15 \times \frac45 \times \frac45 \times \frac45) + (\frac15 \times \frac45 \times \frac45 \times \frac45) + (\frac15 \times \frac45 \times \frac45 \times \frac45) + (\frac15 \times \frac45 \times \frac45 \times \frac45) = 0.410$

What is wrong here? the probability of no kiwi or one kiwi cannot be the same?

Macavity
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twa14
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    Nothing is wrong here, the probabilities are the same and you are correct. – cr001 Nov 04 '15 at 08:38
  • Thanks, I think that I finally see it, even though it is a strange result! I suppose its an example of letting the numbers speak for themselves. – twa14 Nov 04 '15 at 10:00

1 Answers1

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Community wiki answer to allow the question to be answered:

As cr001 pointed out in a comment, nothing is wrong, the proabilities are the same and you are correct.

joriki
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