Area of intersection of 4 quadrants present in a square

Asked Nov 07 '15 at 14:37

Active Nov 07 '15 at 14:44

Viewed 49 times

If I were to draw 4 quadrants of circle inside a square, with each right angle being the angle between the arms of the quadrants, what will be the area of intersection.

Now I've tried this a few times and there's no way to find the area of the inner squarish figure which occurs twice in the intersection.

Finally, a preemptive apology, I am just a 15-year old who is a semi-Maths enthusiast who is unaware of proper terminologies.

The diagram (pardon, sire for 'tis drawn by me): https://i.stack.imgur.com/EzCrz.jpg

edited Nov 07 '15 at 14:44

asked Nov 07 '15 at 14:37

qedk

5

http://math.stackexchange.com/questions/977998/how-calculate-the-shaded-area-in-this-picture – mathlove Nov 07 '15 at 14:43
@mathlove Yep. :) Thanks a lot. – qedk Nov 07 '15 at 14:44
How do I close my question? – qedk Nov 07 '15 at 14:47
See my answer in https://www.facebook.com/Infopas-446849762154897/ – Mick Nov 07 '15 at 15:57

Area of intersection of 4 quadrants present in a square

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