Let's say I have Matrix B =
$$
\begin{bmatrix}
-2 & 4\\
3 & 2\\
0 & -1\\
\end{bmatrix}
$$
How would I calculate B/2? Do I just divide each element of B by 2? Please help!
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There isn't such a thing as the division of a matrix by a scalar (or by anything really). I suppose that what you mean is $\frac12 B$. In which case yes, that's what you do. – Nov 15 '15 at 00:11
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@ahmedhussein So B/2 is miswritten? or the same as 1/2B? – non bee Nov 15 '15 at 00:14
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It's miswritten; probably intended as $\frac12 B$. – Nov 15 '15 at 00:16
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1@ahmedhussein $B/2$ is a common and acceptable notation for $\frac 12 B$ – Ben Grossmann Nov 15 '15 at 00:21
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2@nonbee yes. You just divide every element of $B$ by $2$. – Ben Grossmann Nov 15 '15 at 00:21
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@Omnomnomnom, could you write up your excellent comment as an answer, please, so the question doesn't continue to show no answers? – Frentos Jan 07 '16 at 03:02
2 Answers
0
See the comments. Indeed, given a matrix $B$, one computes $B/2$ by dividing all entries of $B$ by $2$.
Ben Grossmann
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If $$B= \begin{bmatrix} -2 & 4\\ 3 & 2\\ 0 & -1\\ \end{bmatrix} $$ then $$\frac{B}{2}= \frac12\begin{bmatrix} -2 & 4\\ 3 & 2\\ 0 & -1\\ \end{bmatrix} = \begin{bmatrix} -1 & 2\\ 1.5 & 1\\ 0 & -0.5\\ \end{bmatrix}$$
So yes, just divide all the elements by $2$.
BLAZE
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