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Suppose that I have a V (speed) vs X (distance) graph as follows : enter image description here

I want to draw V (speed) vs t (time) graph.

enter image description here

But I don't wat to get the graph, I want to get the proper way of transforming graphs. How can I transform V vs X to V vs t?

Regards.

1 Answers1

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let the equation of $v$ vs $x$ graph be $v=ax+b$

Then $$\dfrac{dx}{dt}=ax+b$$

$$\dfrac{dx}{ax+b}=dt$$

Integrate both sides

$$\int \dfrac{dx}{ax+b}=\int dt$$

$$\dfrac{1}{a}\ln(ax+b) = ct$$

you probably know $a$ and $b$ from the graph, find $c$ from initial condition [should be given]

  • Isn't the first equation for V vs t? I have V vs x. – user3021830 Nov 19 '15 at 09:05
  • fixed. thanks for pointing out – slader.com Nov 19 '15 at 09:07
  • Thank you very much for your answer. I am sorry for asking this but it's been almost 20 years since I've been graduated from college and it seems I've forgotten everything about Calculus, how do wet get from the second operation to third, which corresponds to "Solve this to get". Can you please explain it in baby steps? – user3021830 Nov 19 '15 at 09:17
  • I added an update – slader.com Nov 19 '15 at 10:40
  • Thank you very much for the update. Excuse me for further questions, but when integrating we do integrate left side according to x, but right side according to t. Isn't it a bit wrong? Shouldn't we be taking the same integral on both sides; acodring to x or according to t? – user3021830 Nov 19 '15 at 10:45
  • @user3021830 It is called seperation of variables, see here. – Eff Nov 19 '15 at 11:15
  • That was very enlightening. Thank you very much for your help. – user3021830 Nov 19 '15 at 12:03