(w'x+yz')((xz+w)(y+xz'))' I gotten the answer w'xy'z+wyz' however the answer sheet was w'xz' +w'xy'z+w'yz' can anyone confirm?
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1please show your steps, so we can confirm them – Pieter21 Nov 19 '15 at 12:10
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Or consult WolframAlpha, but that only adds even more different solutions (w'xy' + w'yz'):
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