I know that the polar of an Euclidean unit ball is itself, but I wonder what if its center is not in the origin, like: $$ B=\{(x,y)\in \mathbb R^2 \mid(x-1)^2+y^2\le1\} $$ and the polar of a set is: $$ B^{\circ} = \{ c \in \mathbb{R}^{n} \mid \langle c,x \rangle \leq 1 \quad \forall x \in B \} $$ Please show me some details, thank a lot!!
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2Let $x = 1 + \cos(t)$, you figure out the reset. – IAmNoOne Nov 24 '15 at 03:18
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so it's (x+1)^2+y^2<=1~~ a little weird~~ – user272101 Nov 24 '15 at 05:23