$$f(x,y)=\frac{2^{xy}-1}{|x|+|y|}$$
I got to the conclusion that there is no limit, but I am not sure how to prove it.
$$f(x,y)=\frac{2^{xy}-1}{|x|+|y|}$$
I got to the conclusion that there is no limit, but I am not sure how to prove it.
Along the lines $\ x=0$, or $\ y=0$ the limit is zero; so the limit is zero or it doesn't exist.
Now, in the other cases, you can write the limit in this way: $$\ \lim_{(x,y)\to(0,0)}\frac{2^{xy}-1}{|x|+|y|}=\lim_{(x,y)\to(0,0)}\frac{2^{xy}-1}{xy}\cdot \frac{xy}{|x|+|y|}=$$ $$\ =\lim_{(x,y)\to(0,0)}\ln 2\cdot \frac{xy}{|x|+|y|}$$
Where I used the known limit $\ \lim_{t\to0}\frac{a^t-1}{t}=\ln a$, for $\ a>0,$ with $\ xy=t$
And now, it is easy to show that the last limit is zero:
$$\ |\frac{xy}{|x|+|y|}|≤\frac{|xy|}{|x|}=|y|\to 0$$