Can not resolve integral

Question

I am doing an exercise about surface integral. I think that all my steps are good and that I am just blocking on the last step of the calculations, which is, if my steps are right,

$$ \int_0^1 u^2\sqrt{1+4u^2}\;du $$

I don't figure out how to solve it, can someone help?

I would try the substitution $u=\dfrac12\sinh t$. – Jyrki Lahtonen Dec 09 '15 at 20:59 — Jyrki Lahtonen, Dec 09 '15 at 20:59

score 2 · Answer 1 · answered Dec 09 '15 at 20:59

2

Hint. Try the substitution: $$u=\frac{\tan(s)}{2}.$$

answered Dec 09 '15 at 20:59

C. Falcon

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Can not resolve integral

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