Let ABC be a triangle. Let B' and C' denotes respectively the reflection of B and C in the internal angle bisectors of angle A. How do I prove that the triangles ABC and AB'C' have same incenter.
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Hint. The incentre of AB'C' is obtained by reflecting the incentre of ABC about the bisector.
David
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This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post - you can always comment on your own posts, and once you have sufficient reputation you will be able to comment on any post. - From Review – S - Dec 10 '15 at 08:33
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@Adolfo For pedagogical reasons, I felt in this instance that it would be more helpful to the OP to receive a hint, leaving room for them to discover some steps for themselves, than a complete answer. – David Dec 10 '15 at 08:35
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Triangles $ABC$ and $AB'C'$ are symmetric over the angle bisector of $A$ and hence so do their incenters. Also since the incenters lies on the bisector they must be the same point.
cr001
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