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My teacher told me there are two equations. But I cannot understand why this should be true. Can anyone help to go through this?

Hosein Rahnama
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Renner Francis Rallos
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  • Hint: From H.R.'s picture, observe that the centre of the required circle lies on the perpendicular bisector of the two given points. Think about "tangent to the $y$-axis to formulate a circle, substitute the two points. – GNUSupporter 8964民主女神 地下教會 Dec 13 '15 at 08:13
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    "My teach told me there are two equations." is not a question at all. Please make the body of the question self contained. – Asaf Karagila Dec 13 '15 at 09:20
  • I know the question is already on hold as off-topic, but I feel the need to also point out that it is a possible duplicate of http://math.stackexchange.com/q/101986/145141. – gebruiker Dec 13 '15 at 11:11

1 Answers1

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Hints

$1.$ This picture will help you to imagine better. :)

$2.$ The equations of the circles are

$$\begin{array}{} \color{green}{\text{Green:}} & (x-3)^2+(y-4)^2=25 \\ \color{red}{\text{Red:}} & (x-15)^2+(y+8)^2=225 \end{array}$$

enter image description here

Hosein Rahnama
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