I am learning signals and systems. I solve the problem and reach the equation (5.164). How can I work out the value of $A$ and $B$?
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We are trying to find $A$ and $B$ such that
$\dfrac{1}{[1-(re^{j\theta})e^{-j\Omega}][1-(re^{-j\theta})e^{-j\Omega}]} = \dfrac{A}{1-(re^{j\theta})e^{-j\Omega}}+\dfrac{B}{1-(re^{-j\theta})e^{-j\Omega}}$
holds for all values of $\Omega$.
Multiply both sides by $[1-(re^{j\theta})e^{-j\Omega}][1-(re^{-j\theta})e^{-j\Omega}]$ to get:
$1 = A[1-(re^{-j\theta})e^{-j\Omega}] + B[1-(re^{j\theta})e^{-j\Omega}]$
$1 = (A+B) - (re^{-j\theta}A+re^{j\theta}B)e^{-j\Omega}$
In order for this to hold for all values of $\Omega$, we need $A+B = 1$ and $re^{-j\theta}A+re^{j\theta}B = 0$.
Solving this system of equations yields $A = \dfrac{e^{j\theta}}{2j\sin\theta}$ and $B = -\dfrac{e^{-j\theta}}{2j\sin\theta}$.
JimmyK4542
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