The equation
$$
f(x)-g(x)=(f-g)(x) \quad (*)
$$
features the functions $f$ and $g$ and a third function $f-g$ which is the difference function of $f$ and $g$.
It also uses $x$ which is some element from the domain set of $f$, $g$ and $f-g$, an argument to those functions, a value which these functions map to some element of their codomain set which is also called the image of the function:
In mathematics $f(x)$ is the value that the function $f$ maps the argument $x$ to.
Example:
$$
f : D \to A \\
f(x) = x^2 + 1 \in A \quad (x \in D)
$$
will map an $x$ from some domain set $D$ (here unspecified) to the image set $A$. What to do with the argument $x$ to get $f(x)$ is given as an expression in this example.
The given equation $(*)$ can be read as a definition for the function $f-g$. It works by defining the function value $(f-g)(x)$ as difference of the function values $f(x)$ and $g(x)$, for arbitrary $x$ from the domain set.
Similar definitions are used to define $f + g$ (sum), $f g$ (product), $f/g$ (quotient), $f \circ g$ (composition), $c f$ (multiplication by a constant), $f'$ (taking the derivative) and more.