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$$Error = \vert(\tan(\theta)*20 – (9.8/2V^2(\cos\theta)^2)*20^2 - 2.2)\vert$$

$\vert\bullet\vert $ indicate absolute value.

Is it possible to manually minimise the above equation and if so how do I go about it? Here both $\theta$ and $V$ are the independent variables and $Error$ is the dependent variable. I need to minimise the error.

user300228
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  • As I see it, the formula you wrote reads $$ Error=\left\vert 20\tan(\theta)-20^2\cdot\frac{9.8}{2}V^2\cos^2(\theta)-2.2\right\vert$$ Is it what you had in mind? –  Dec 21 '15 at 17:34
  • Or are the $V$ and $\cos \theta$ part of a denominator? – Laurent Duval Dec 21 '15 at 17:35
  • Sorry for my poorly written statement, but yes the V and cos theta are part of the denominator – user300228 Dec 22 '15 at 01:32

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