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In a trapezium $ABCD$, $AB||CD$, angle$B$ = $\frac{1}{2}D$. If $AD = q$ and $DC = p$, find $AB$.

urkarsh jain
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1 Answers1

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Draw the bisector of angle D, which must be parallel to BC to meet AB at X. Triangle AXD is isosceles, and XBCD is a parallelogram,so $AX + XB = AB= p+q$

David Quinn
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