if $a|b$ and $a|c$, does it mean that $b|c$?
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No. Let $b=ak$, $c=am$ with $k>m\ge 1$. – user236182 Jan 01 '16 at 20:21
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No, consider $3|9$ and $3|15$ but $9$ does not divide $15$.
Gregory Grant
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is there any way to link the two together with a common divisor? GCD not known? Because I want to show $b|c$ and only have that information? For example $b|kc$ where $k$ is an integer? – LucasCK Jan 01 '16 at 20:16
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Yes you can say that $a|b$ and $a|c$ implies $a|gcd(b,c)$. That's about the best you can say. – Gregory Grant Jan 01 '16 at 20:18
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I'm afraid the most you can possibly conclude if all you know is $a|b$ and $a|c$ is that $a|gcd(b,c)$. You would need more information to say something stronger than that. – Gregory Grant Jan 01 '16 at 20:22
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$a\mid b$ and $a\mid c$ is equivalent to $a\mid \gcd(b,c)$ (not only implied). – user236182 Jan 01 '16 at 20:23
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