Let ABC be a triangle with $AB=c, BC=a, CA=b$. Let I be the incenter and G be the centroid of ABC. Assume that $GI$ perpendicular to $CI$. Prove that $6ab=(a+b)(a+b+c)$. I don't have any idea how to solve it.
The problem is the same as this one: How to prove that $ 6ab=(a+b)(a+b+c)$ for triangle
But I would like a synthetic proof without trilinear coordinates (meaning using only Euclid's axioms). I were triying many thing but I didn't prove it. I anyone has any idea please I don't want a full solution.
Thanks