One source of nice examples is the operator of multiplication by $z$ on $L^2(\mu)$ where
$\mu$ is a probability measure on a subset of the complex plane (a bounded subset if you want a bounded operator). These are normal operators, so there is no residual spectrum.
$\lambda$ is in the point spectrum iff $\mu(\{\lambda\}) > 0$. This is not necessarily discrete. For example, there are probability measures that assign
positive probability to each rational in $[0,1]$, but to no irrationals. This is an example where the point spectrum is not discrete and the continuous spectrum is not open.
EDIT:
For an example where the continuous spectrum is discrete, consider a case where $\mu$ assigns probability $1/n - 1/(n+1) > 0$ to $1/n$ for each natural number $n$. Then the continuous spectrum is $\{0\}$.