Can anybody recommend a symbol for ‘equal if defined’ as an asymmetric concept?
In contexts where one might write down notation for an undefined quantity (such as $1/x$ when $x$ might be $0$), sometimes people use the equality symbol to mean that if either side is defined, then so is the other, and then they are equal; and sometimes people use it to mean that if both sides are defined, then they are equal. Sometimes they use this together with a variant symbol with the other meaning. These are not the meanings that I want.
I want a symbol that says that if the left-hand side is defined, then so is the right-hand side, and then they are equal. Or a symbol that means that if the right-hand side is defined, then so is the left-hand side, and then they are equal. Either way, the meaning is asymmetric. Preferably a symbol that is itself left-right asymmetric, so that the reverse symbol has the reverse meaning.
Usage examples: In Algebra, when we write that $(x^2 - 1)/(x^2 - x) = (x + 1)/x$, what we really mean is that if $(x^2 - 1)/(x^2 - x)$ is defined, then $(x + 1)/x$ is also defined and then $(x^2 - 1)/(x^2 - x)$ is equal to $(x + 1)/x$. However, if $(x^2 - 1)/(x^2 - x)$ is undefined, then we're not claiming that it's equal to anything, and we're also not saying whether $(x + 1)/x$ is defined.
In Calculus, when we write that $\lim_{x \to c}(f(x) + g(x)) = \lim(f(x)) + \lim(g(x))$, what we really mean is that if $\lim(f(x)) + \lim(g(x))$ is defined, then $\lim(f(x) + g(x))$ is also defined and then $\lim(f(x) + g(x))$ equals $\lim(f(x)) + \lim(g(x))$. However, if $\lim(f(x)) + \lim(g(x))$ is undefined, then we're not claiming that anything's equal to it, and we're also not saying whether $\lim(f(x) + g(x))$ is defined.
Of course, one can always write ‘if the left-hand side is defined’ after the equation, or something like that. But I want a symbol that I can use with a string of conditional equalities (all in the same direction) in the course of an argument to establish an overall conditional equality. Example: $\lim_{x \to 5}(x^2 + 6) = \lim(x^2) + \lim(6) = \lim(x)^2 + 6 = 5^2 + 6 = 31$, where at each stage I use a basic rule of limits in the course of the calculation. Ultimately, I conclude that if $31$ is defined (which it is), then $\lim(x^2 + 6)$ is defined and equals $31$ (which it does).
Of course, I can make up a symbol, but if anybody has already made one up and used it successfully (either in a formal logical context or informally as I was doing above), then I'd like to hear about that.