Very simply: $$a\log(b) +\log(c)$$
The coefficient on the first term is throwing me off.
Very simply: $$a\log(b) +\log(c)$$
The coefficient on the first term is throwing me off.
Recall the properties $$a \log b = \log b^a$$ and $$\log a +\log b = \log ab.$$ Thus $$a\log b +\log c = \log b^a+\log c = \log(b^ac).$$
You can write $a\log(b) +\log(c)=\log(b^ac).$ Past that, there's not a lot we can do.