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Thanks for your help. I'm not too sure if this is the correct way to answer this question, but let me know!

A student is having issues with an online computing grading system.
The system is displaying his term grade, but not his actual test result.
The term grade was at 0.00% yesterday, until today when it was 12% - the 12% is from the test which he sat recently, and the ONLY test he sat this term.

If the test he sat recently was weighted at 20% of term grade, and the mark displayed was 12% (due to the mark being 20%), what is his final mark for the first test? REMEMBER - he has not sat any other tests yet, but the mark displayed is worth 20%

From my understanding it's simply just 12*5 = 60% ?

Thanks!

Alex
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1 Answers1

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Let's approach it in a different way-

He got $12$ marks out of $100$.

That $100$ was $20\%$ of $500$

So, he got $12*5=60$ marks out of $500$!!

Since he attempted only the $100$ mark test, He got $60$ marks out of $100$!!

Win Vineeth
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  • Thank you! But lets say if the student attempted test A ONLY.

    And the grades were ranked as follows:

    Test A(20.0%), Test B(25.0%), Test C(30.0%), Test D(25.0%) Would this still mean he got 60 percent for that specific test A?

     – Alex Feb 16 '16 at 07:11
  • @Alex Yes, the same rule still holds.. regardless of what the other $80%$ which didn't attempt , is. – Win Vineeth Feb 16 '16 at 07:13
  • thanks, sorry so you mean that even though he didn't attempt the other 80%, he still received 60% for that test A? – Alex Feb 16 '16 at 07:14
  • @Alex Absolutely. He received $60%$ in that test A – Win Vineeth Feb 16 '16 at 07:17