In a circle, ABCD is a cyclic quadrilateral and PQ is a diameter. PQ intersects the side AD and BC. Prove that QC and AP bisect Angle C and Angle A respectively.
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A picture would be very helpful. Unfortunately, it doesn't seem to be true. – robjohn Feb 18 '16 at 15:08
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1I think it is the other way around, i.e., if you consider the bisectors of C and A then their intersections with the circle always identify a diameter. – Giovanni Resta Feb 19 '16 at 13:19