The coefficient of $x^{26}$ in expansion of $(1+x)^{41}(1-x+x^2)^{40}$ is ? Answer is $2082$ now on simplifying i get it as $(1+x^3)^{40}.(1+x)$ now this nowhere gives any coefficient with x to power of $26$ . Wheres my mistake .Thanks!
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1So, the coefficient is $0$ – lab bhattacharjee Feb 19 '16 at 10:44
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From where do you have the 'answer' $2082$? – gammatester Feb 19 '16 at 10:45
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Its given in my book – Archis Welankar Feb 19 '16 at 10:51
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1I would suggest either the book has stated the wrong answer or you have not shown the correct expression that is stated in the book. Books can and do have mistakes in them. – Mufasa Feb 19 '16 at 11:15