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A marksman fires a bullet from a gun with a horizontal speed of $360ms^{-1})$ The mass of the gun is $3kg$.

The gun recoils into the marksman's shoulder with a horizontal speed of $6ms^{-1}$.

Find the mass of the bullet.

The gun comes to rest after $1/18$ seconds.

I get lost attempting this question and don't understand what method to use.

StrangeApple
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  • Use conservation of momentum – David Quinn Feb 25 '16 at 20:58
  • $6 \mathrm m \mathrm s^{-2}$ is not a speed, it's an acceleration. I guess in the original statement of this question, that is the acceleration that occurs to the gun as it pushes against the marksman's shoulder. – David K Feb 25 '16 at 21:03
  • Is it as simple as $360 * m = 6 *3$ $m=18/36$ $m=0.5$ – StrangeApple Feb 25 '16 at 21:03
  • Edited speed, there was incorrect units. It should be $ms^{-1}$, it should now be corrected. – StrangeApple Feb 25 '16 at 21:05
  • That's starting to sound reasonable, just be careful with the decimal point (and the number of digits); I don't think the bullet is supposed to weigh 500 grams. If the new problem statement is correct then the $1/18$ seconds is just a red herring. – David K Feb 25 '16 at 21:15
  • I've just realised my mistake, it should be $360∗m=6∗3m$ So $m=18/36 = 0.05$ , 50g grams sounds more reasonable for the mass of the bullet. – StrangeApple Feb 25 '16 at 21:17

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