paths and curves

Question

Let the path $c(t): \mathbb{R}\rightarrow \mathbb{R}^2$ be defined by $c(t)=(\sin(t)+2, 1/(\sin(t)+2))$

How can I find the location of the path at $t=n\pi$ where $n$ is any integer?

I plugged $\pi$ into $c(t)$ and I got $(0,1/2)$ for all $n$ but $(0,1/2)$ doesn't lie on the curve. I'm not sure what else to do.

@agriffin $c(n\pi) = (2,1/2)$ not $(0,1/2)$. – GaussTheBauss Feb 25 '16 at 22:26 — GaussTheBauss, Feb 25 '16 at 22:26
Ahh thank you for catching that! – agriffin Feb 25 '16 at 22:32 — agriffin, Feb 25 '16 at 22:32

score 0 · Answer 1 · answered Feb 25 '16 at 23:51

0

Community wiki answer so the question can be marked as answered:

As remarked in a comment, substituting $t=n\pi$ yields $2$ in the first coordinate, not $0$.

answered Feb 25 '16 at 23:51

joriki

1 Answers1