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$1458^n = 2^n / 9$

I'm told to find the value of $n$. How to do that?

It is my first time encountering this type of problem when I can't find make every number a constant . What do I do here . Can I get a hint ? Thanks in advance

(2 x 3^6)^n x 3^2 = 2^n

user307640
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$$1458^n=\frac{2^n}{9}$$

$$729^n\cdot 2^n=\frac{2^n}{9}$$

$$729^n=\frac{1}{9}$$

$$9^{3n}=9^{-1}$$

$$3n=-1$$

$$n=-\frac{1}{3}$$

Itakura
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