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The proof I have to solve is:

$$\lnot Z,~ \bigg((\lnot Z \lor S) \lor T\bigg) \implies L \vdash L \lor T$$

Basically I have tried to work backwards trying to prove the contradiction of $L \lor T$ but cannot seem to find how to connect these two parts, am I doing to much work or something wrong??

DanielV
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1 Answers1

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Since you know $\neg Z$ we may use $\vee-$introduction to show $(\neg Z\vee S)\vee T$. Thus using modus ponens ($\rightarrow-$elimination) we may conclude $L$. Now use $\vee-$introduction on $L$ to conclude $L\vee T$, and we are done.

Ove Ahlman
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