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I am working though the proof of Proposition 6.2 in Erdmann's "Introduction to Lie Algebras".

I can't verify that every Lie subalgebra of $L \subseteq \mathfrak{gl}(V)$ contains a maximal (proper) Lie subalgebra.

How would I prove this fact?

el_tenedor
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1 Answers1

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If the dimension of $V$ is finite, consider $S(L)$ the of Lie subalgebras distinct of $L$, it is not empty since it contains $0$, an element of maximum dimension is a maximum proper Lie subalgebra.