If we take the absolute value for sin function, then it becomes even.
However, isn't period of this function $\pi$?
To find fourier series, 1.Even 2. period $2 \pi$.
Can we just treat this function as period $2\pi$?
Asked
Active
Viewed 223 times
1
-
1If a function is periodic with period $T$, then it is periodic with period $kT$, for any $k\in \mathbb{N}$. – Alberto Debernardi Apr 26 '16 at 07:32
-
if $f(x)$ is $\pi$ periodic (and its Fourier series converge) then $f(x) = \sum_{n = -\infty}^\infty a_n e^{4 i \pi n x}$ so writing it $f(x) = \sum_{n = -\infty}^\infty c_n e^{2 i \pi n x}$ you have $c_{2n + 1} = 0$ – reuns Jul 17 '16 at 22:26