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I am not sure where to start on this question.

I am not sure how to fit the coordinates into the equation $y=\log_3(x-4)$

Michael Hardy
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dagda1
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  • (q,2) is point on the graph so setting x to q and y to 2 you get $2 = \log_3 (q-4) $. Solve for q. Which you do by rising three to each side to get $3^2 = x+4$. That's all. – fleablood Apr 30 '16 at 08:07

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It's just $3^y=x-4$ so as $q,2$ lies on it we have $9=q-4$ thus $q=13$

Archis Welankar
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