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Does any know how to find the closed form of integral $\int_a^b e^{-ix^2} dx$ for any real $a$ and $b$. It seems that I need to use the fresnel integrals.

Murray.A
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1 Answers1

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$$\int_a^b e^{-ix^2} dx = \int_a^b \cos x^2 dx - i\int_a^b \sin x^2 dx$$

Paul Sinclair
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