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If a polynomial $P$ with integer coefficients has three distinct integer zeros, then show that $P(n)\neq1$ for any integer $n$.

1 Answers1

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Sketch:

  1. Suppose that $P(a)=P(b)=P(c)=0$ where $a,b,c$ are integers.

  2. Suppose that there exists a $d$ such that $P(d)=1$.

  3. Prove that $(d-a)\mid P(d)-P(a)=1$. Hint: Prove $(d-a)\mid (d^k-a^k)$ by factoring.

  4. This gives three distinct divisors of $1$, do you detect a contradiction?

Michael Burr
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