In this example, for the third and the fourth element of the second column of matrix L, aren't them should be $m_{32}$ and $m_{42}$. And according to the definition,$m_{32}=a_{32}/a_{22}$, which in this case, should be $-1/1=-1$. Where does the 4 come from?
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The result is correct. – Moo May 07 '16 at 02:06
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Where did you get the 4? – J.doe May 07 '16 at 02:14
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$l_{31}u_{12} + l_{32}u_{22} = -1 \rightarrow 3\times 1 + l_{32}\times - 1 = -1 \implies l_{32} = 4$. – Moo May 07 '16 at 02:29
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but the formula in the book is $l_{32}=m_{32}=a_{32}/a_{22}$ – J.doe May 07 '16 at 02:43
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In general, it's $l_{ji}=m_{ji}=a_{ji}/a_{ii}$ – J.doe May 07 '16 at 02:43
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Depends which $LU$ you are doing. The result shows they are using this one http://nucinkis-lab.cc.ic.ac.uk/HELM/workbooks/workbook_30/30_3_lu_decomposition.pdf – Moo May 07 '16 at 02:47
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Are there different kinds of LU? – J.doe May 07 '16 at 03:37
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1http://math.stackexchange.com/questions/485513/what-are-pivot-numbers-in-lu-decomposition-please-explain-me-in-an-example – Moo May 07 '16 at 03:48
