$$a^{bx} = c$$
Solve for x
$$\log a^{bx} = \log c$$
$$bx \log a = \log c$$
$$x = \frac{\log c}{b \log a}$$
Is this correct?
Thanks :)
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Yes, it is correct. I am assuming that $a$ is positive. – André Nicolas May 08 '16 at 05:15
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What are the ranges of the parameters and the variable? – joriki May 08 '16 at 05:32
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@joriki: Ranges aren't mentioned in the question – Zantheor May 08 '16 at 05:40
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@Andre: thanks! – Zantheor May 08 '16 at 05:41
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You are welcome. – André Nicolas May 08 '16 at 05:41
1 Answers
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Community wiki answer so the question can be marked as answered:
No ranges are given. As André noted in a comment, some assumptions are required. If $a$ is assumed to be a positive real number, your calculation is correct.
joriki
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