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I have a question that says,

Explain how to disprove a theorem of the logical form "$\forall x \in A, P(x)$". Write the logical form of the statement you want to prove.

So disprove a theorem, wouldn't you just find a counterexample because it doesn't matter what logical form the equation is in right? Then for the logical statement you want to prove, would it just be the negation of "$\forall x \in A,P(x)$"?

Siong Thye Goh
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You are right in saying that you should find a counterexample. The logical form of this counterexample would state that $\exists x \in A, \neg P(x)$. (When you're dealing with logic, you have to be careful how you perform the 'negation'.)

shardulc
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Yes you are correct. One counterexample is enough to disprove a theorem.

You can check whether it is a counterexample by taking all conditions for the theorem and then negating the proposition.

So if you have for example $\forall_{x \in A} : P(x)$, where $P$ is your proposition. Then negating this turns into $\exists_{x \in A} : \neg P(x)$, which disproves the theorem.

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    To disprove such a theorem, one counterexample is enough. But that's not so for other types of theorems, i.e. theorems whose form isn't "for all ...". – zipirovich May 23 '16 at 17:29