It is estimated that 20% of students take an active part in a sports club in college. If 20 students are randomly sampled and asked if they are active participants in a college sports club what is the probability that more than 4 are active in a sports club?
So I am setting this up as a binomial and finding '1 - (p(0)+p(1)+p(2)+p(3)+p(4))'
However the N value is 20. Is there a simpler way of determining this?
notice that 20! = 201918....1, and 17! = 1716...1. So dividing them gives: 20!/(17!3!) = (201918)/(321) = 10196.
– Nescrio May 26 '16 at 20:09