I guess you are supposed to conclude that occurrences of faces 3. 5. and 6
together amounted to $1200 - 595 = 605$, but are given no information
on how many times each of these faces appeared.
In that case you can do a chi-squared goodness of fit test
with four categories: '1', '2', '4', and '356'. Their observed
counts are 190, 220, 185, and 605, and their expected counts
are 200, 200, 200, and 600, respectively. Then the chi-squared
goodness-of-fit statistic is $Q = 3.67.$ Under the null
hypothesis that the die is fair, $Q \stackrel{approx}{\sim} Chisq(df = 3).$
X = c(190, 220, 185, 605)
E = c(200, 200, 200, 600)
Q = sum((X-E)^2/E); Q
## 3.666667
Since you know something about such tests, and hoping that I
have cleared up whatever was confusing you about this problem,
I suppose you can take it from there to determine whether
to judge that the die is unfair. (The problem would have been
straightforward if you had been given observed frequencies
for all six faces of the die.)