Can anybody please explain me the reason for last 6th line.
(The set of all vectors at all points...)
Asked
Active
Viewed 51 times
0
User
- 2,938
1 Answers
2
$p\in\mathbb{R}^{n+1}$ and so is $v$, hence the pair $(p,v)$ can be seen as living in $\mathbb{R}^{n+1}\times\mathbb{R}^{n+1}$ which is $\mathbb{R}^{2n+2}$.
Justin Benfield
- 3,992
-
Okie got it. Thanks. – User Jun 08 '16 at 08:42