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How does the Squeeze Principle used to find that $\lim_{x \rightarrow \infty} \sin x / x$? I understand what the squeeze principle is, but do not understand how to use it for this example.

Romeo
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    Hint: $-1/x \leqslant \sin x / x \leqslant 1/ x$ Now take limits as $x \to \infty$. – RRL Jun 08 '16 at 22:53

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Using the basic fact that $-1\leq \sin x\leq1,$ we get $$-\frac{1}{x}\leq \frac{\sin x}{x}\leq\frac{1}{x}.$$ Now apply Squeeze theorem.

Kushal Bhuyan
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