Does a sequence that is eventually constant contain less terms than one that is not?
I don't know how to properly think about this, one could either argue that
a sequence : 1 2 3 1 1 1 1 1 1 1 1 ..., contains as many terms as 1 2 3 4 5 6 7...
or one could say that the sequence only contains 3 terms, whereas the other contains $\mathbb{N}$ many terms
What is the correct way to think about this