Searching Riemann zeta zeros in nuclear data files.

Question

Is this match between some of the truncated Riemann zeta zeros and numbers in nuclear calculation data only a coincidence?

I calculated these numbers from the Riemann zeta zeros and looked them up in Google:

1.55974324 found at https://www-nds.iaea.org/point2004/k300/ZA026054
1.34835538 found at https://www-nds.iaea.org/point2009/100eV/ZA020042
1.28559070 not found at iaea
1.22938585 not found at iaea
1.21018709 found at https://www-nds.iaea.org/point2004/1KEV/ZA096242
1.18195215 not found at iaea
1.16596938 found at https://www-nds.iaea.org/point2009/K2100/ZA032074
1.15605984 found at https://www-nds.iaea.org/point2009/1keV/ZA032076
1.13983743 not found at iaea
1.13454842 not found at iaea
1.12593870 not found at iaea
1.11774439 not found at iaea
1.11167947 not found at iaea
1.10881056 not found at iaea
1.10130661 not found at iaea

The numbers are of the form:

$$\exp \left(\frac{1}{\frac{\Im(\rho _n)}{2 \pi }}\right)$$

where $n=1$ to $15$

I guess this question will get down voted, and I will delete it when that happens.

Answer 1

I googled $50$ numbers of this form, with a $1$ before the decimal point and $8$ manually randomised digits after the decimal point. Of these, $2$ were found in https://www-nds.iaea.org/point2004. Thus the probability of such a number being found can be estimated to be roughly $\frac1{25}$. Of the $15$ numbers you searched for, you found $2$ in this directory. The probability for this to happen is estimated at $\binom{15}224^{13}/25^{15}\approx10\%$, so this is not a remarkable event.

I was going to repeat the experiment with the entire site, https://www-nds.iaea.org, but when the very first two numbers I tried were hits, I figured that this is a waste of time and I don't understand why you didn't try this yourself, since I usually find your other contributions to the site quite interesting.