Permutations (Making numbers from digits)

Question

Using the digits 1, 2, 4, 5, 7, and 8, how many different three-digit numbers can you form if each digit may be repeated any number of times in a number?

I have tried to do this question and tried to find the answer, unfortunately all the answers were of the question topics "no repeats in digits." Please help me!

What have you tried? Showing your attempts really helps people know how to talk about this problem with you. — Matthew Conroy, Jun 25 '16 at 02:27

score 2 · Accepted Answer · answered Jun 25 '16 at 02:37

2

You have $6$ digits in all and each place of a three-digit number can be filled by $6$ ways. Hence, by multiplication rule; $6×6×6=216$ numbers.

answered Jun 25 '16 at 02:37

Nitin Uniyal

7,946

Permutations (Making numbers from digits)

1 Answers1